JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Diameter of a steel ball is measured using a Vernier callipers which has divisions of \(0. 1\,cm\) on its main scale \((MS)\) and \(10\) divisions of its vernier scale \((VS)\) match \(9\) divisions on the main scale. Three such measurements for a ball are given as
| S.No. | \(MS\;(cm)\) | \(VS\) divisions |
| \((1)\) | \(0.5\) | \(8\) |
| \((2)\) | \(0.5\) | \(4\) |
| \((3)\) | \(0.5\) | \(6\) |
- A \(0.52\)
- B \(0.59\)
- C \(0.56\)
- D \(0.53\)
Answer & Solution
Correct Answer
(B) \(0.59\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} Lets\,count\, = \frac{{0.1}}{{10}} = 0.01\,\,cm\\ {d_1} = 0.5 + 8 \times 0.01 + 0.03 = 0.61\,cm\\ {d_2} = 0.5 + 4 \times 0.01 + 0.03 = 0.57\,cm\\ {d_3} = 0.5 + 6 \times 0.01 + 0.03 = 0.59\,cm\\ Mean\,diameter\, = \frac{{0.61 + 0.57 + 0.59}}{3}\\…
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