The diameter of the objective lens of microscope makes an angle \(\beta \) at the focus of the microscope. Further, the medium between the object and the lens is an oil of refractive index \(n\). Then the resolving power of the microscope

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(C) increases with increasing value of \(n\, sin\, 2\beta \)

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Resolving power of microscope,

\(\mathrm{R.P.}=\frac{2 \mathrm{n} \sin \theta}{\lambda}\)

\(\lambda=\) Wavelength of light used to illuminate the object

\(\mathrm{n}=\) Refractiveindex of the medium between object and objective

\(\theta=\) Angle

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