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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

The equation for real gas is given by \(\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}\), where \(\mathrm{P}, \mathrm{V}, \mathrm{T}\) and R are the pressure, volume, temperature and gas constant, respectively. The dimension of \(\mathrm{ab}^{-2}\) is equivalent to that of :

  1. A Planck's constant
  2. B Compressibility
  3. C Strain
  4. D Energy density
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Answer & Solution

Correct Answer

(D) Energy density

Step-by-step Solution

Detailed explanation

\begin{aligned} & {\left[\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right](\mathrm{V}-\mathrm{b})=\mathrm{RT}} \\ & \therefore[\mathrm{a}]=[\mathrm{P}]\left[\mathrm{V}^2\right]=\mathrm{ML}^{-1} \mathrm{~T}^{-2} \mathrm{~L}^6=\mathrm{ML}^5 \mathrm{~T}^{-2} \\ &…

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