JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young’s double slit experiment the ratio of the slit’s width is \(4 : 1.\) The ratio of the intensity of maxima to minima, close to central fringe on the screen will be
- A \({\left( {\sqrt 3 + 1} \right)^4}\,:\,16\)
- B \(25\,:\,9\)
- C \(9\,:\,1\)
- D \(4\,:\,1\)
Answer & Solution
Correct Answer
(C) \(9\,:\,1\)
Step-by-step Solution
Detailed explanation
\(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{9}{1}\)
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