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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2019
  • Medium
  • MCQ

In a Young’s double slit experiment the ratio of the slit’s width is \(4 : 1.\) The ratio of the intensity of maxima to minima, close to central fringe on the screen will be

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Answer & Solution

Correct Answer

(C) \(9\,:\,1\)

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Detailed explanation

\(\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{9}{1}\)
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