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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2019
  • Easy
  • MCQ

A string \(2.0\, m\) long and fixed at its end is driven by a \(240\, Hz\) vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is

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Answer & Solution

Correct Answer

(D) \(320\, m/s, 80\, Hz\)

Step-by-step Solution

Detailed explanation

We have:

\(f=\frac{n v}{2 \ell}\)

\(240=\frac{3 \times v}{2 \times 2}\)

\(\Rightarrow \quad v=320 \mathrm{m} / \mathrm{s}\)

Fundamental frequency \(=\frac{v}{2 \ell}=80 \mathrm{Hz}\)

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