JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor has plate area \(40\,cm ^2\) and plates separation \(2\,mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\,mm\) and dielectric constant \(5\) . The capacitance of the system is :
- A \(24 \varepsilon_0\; F\)
- B \(\frac{3}{10} \varepsilon_0\; F\)
- C \(\frac{10}{3} \varepsilon_0\; F\)
- D \(10 \varepsilon_0 \; F\)
Answer & Solution
Correct Answer
(C) \(\frac{10}{3} \varepsilon_0\; F\)
Step-by-step Solution
Detailed explanation
This can be seen as two capacitors in series combination so \(\frac{1}{C_{e q}}=\frac{1}{C_1}+\frac{1}{C_2}\) \(=\frac{1}{\frac{K \in_0 A}{t}}+\frac{1}{\frac{\epsilon_0 A}{d-t}}\) \(=\frac{ t }{ K \in_0 A }+\frac{ d - t }{\epsilon_0 A }\)…
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