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JEE Mains · Physics · STD 11 - 7. gravitation

At a certain depth "\(d\)" below surface of earth. value of acceleration due to gravity becomes four times that of its value at a height \(3\,R\) above earth surface. Where \(R\) is Radius of earth (Take \(R =6400\,km\) ). The depth \(d\) is equal to \(............\,km\)

  1. A \(5260\)
  2. B \(640\)
  3. C \(2560\)
  4. D \(4800\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4800\)

Step-by-step Solution

Detailed explanation

\(\frac{ GM }{ R ^2}\left[1-\frac{ d }{ R }\right]=\frac{4 \times GM }{(4 R )^2}\) \(1-\frac{ d }{ R }=\frac{1}{4} \Rightarrow \frac{ d }{ R }=\frac{3}{4} \Rightarrow d \frac{3}{4} R\) \(d =4800\,km\)
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