JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The formula \(X = 5YZ^2\), \(X\) and \(Z\) have dimensions of capacitance and magnetic field respectively. What are the dimensions of \(Y\) in \(SI\) units?
- A \([{M^{ - 2}}\,{L^0}\,{T^{ - 4}}\,{A^{ - 2}}]\)
- B \([{M^{ - 3}}\,{L^{-2}}\,{T^8}\,{A^{ 4}}]\)
- C \([{M^{ - 2}}\,{L^{-2}}\,{T^6}\,{A^3}]\)
- D \([{M^{ - 1}}\,{L^{-2}}\,{T^4}\,{A^2}]\)
Answer & Solution
Correct Answer
(B) \([{M^{ - 3}}\,{L^{-2}}\,{T^8}\,{A^{ 4}}]\)
Step-by-step Solution
Detailed explanation
\(X{\kern 1pt} = 5Y{Z^2}\) \(Y{\kern 1pt} = \frac{X}{{5{Z^2}}} = \,{M^{ - 3}}{L^{ - 2}}{T^8}{A^4}\)
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