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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2021
  • Medium
  • MCQ

If the time period of a two meter long simple pendulum is \(2\, s\), the acceleration due to gravity at the place where pendulum is executing \(S.H.M.\) is

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Answer & Solution

Correct Answer

(C) \(2 \pi^{2}\, ms ^{-2}\)

Step-by-step Solution

Detailed explanation

\(T =2 \pi \sqrt{\frac{l}{ g }}\)

\(2=2 \pi \sqrt{\frac{2}{ g }}\)

\(\Rightarrow g =2 \pi^{2}\)

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