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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2022
  • Medium
  • MCQ

The electric current in a circular coil of \(2\) turns produces a magnetic induction \(B _{1}\) at its centre. The coil is unwound and is rewound into a circular coil of \(5\) turns and the same current produces a magnetic induction \(B _{2}\) at its centre.The ratio of \(\frac{ B _{2}}{ B _{1}}\) is.

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Answer & Solution

Correct Answer

(B) \(\frac{25}{4}\)

Step-by-step Solution

Detailed explanation

\(B=\frac{N \mu_{0} 1}{2 R}\)

\(B_{1}=\frac{N_{1} \mu_{0} i}{2 R_{1}}\)

For \(N _{2}=5\)

Radius of coil \(= R _{2}=\frac{ N _{1} \times R _{1}}{ N _{2}}\)

\(B _{2}=\frac{ N _{2} \mu_{0} i }{ R _{2}}\)

\(\frac{ B _{2}}{ B _{1}}=\frac{ N _{2}}{ N _{1}} \frac{ R _{1}}{ R _{2}}=\frac{ N _{2}}{ N _{1}} \times \frac{ N _{2}}{ N _{1}} ; \quad \frac{ B _{2}}{ B _{1}}=\frac{25}{4}\)

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