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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2021
  • Hard
  • MCQ

A scooter accelerates from rest for time \(t_{1}\) at constant rate \(a _{1}\) and then retards at constant rate \(a _{2}\) for time \(t _{2}\) and comes to rest. The correct value of \(\frac{t_{1}}{t_{2}}\) will be ..... .

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Answer & Solution

Correct Answer

(B) \(\frac{ a _{2}}{ a _{1}}\)

Step-by-step Solution

Detailed explanation

Draw vt curve

\(\tan \theta_{1}=a_{1}=\frac{v_{\max }}{t_{1}}\) And \(\tan \theta_{2}=a_{2}=\frac{v_{\max }}{t_{2}}\)

\(\div\) above

\(\frac{t_{1}}{t_{2}}=\frac{a_{2}}{a_{1}}\)

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