JEE Mains · Physics · STD 12 - 13. Nuclei
Imagine that a reactor converts all given mass into energy and that it operates at a power level of \(10^9\, watt\). The mass of the fuel consumed per hour in the reactor will be : (velocity of light, \(c\) is \(3\times10^8\, m/s\))
- A \(0.96\, gm\)
- B \(0.8\,gm\)
- C \(4\times10^{-2} \,gm\)
- D \(6.6\times10^{-5} \,gm\)
Answer & Solution
Correct Answer
(C) \(4\times10^{-2} \,gm\)
Step-by-step Solution
Detailed explanation
Power level of reactor, \(P=\frac{E}{\Delta t}=\frac{\Delta m c^{2}}{\Delta t}\) mass of the fuel consumed per hour in the reactor, \(\frac{\Delta m}{\Delta t}=\frac{P}{c^{2}}=\frac{10^{9}}{\left(3 \times 10^{8}\right)^{2}}=4 \times 10^{-2} \mathrm{gm}\)
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