JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A circular coil having \(N\,turns\) and radius \(r\) carries a current. It is held in the \(XZ\) plane in a magnetic field \(B\hat i\) . The torque on the coil due to the magnetic field is
- A \(\frac{{B{r^2}I}}{{\pi N}}\)
- B zero
- C \(\frac{{B\pi {r^2}I}}{N}\)
- D \({B\pi {r^2}IN}\)
Answer & Solution
Correct Answer
(D) \({B\pi {r^2}IN}\)
Step-by-step Solution
Detailed explanation
\( \text { Magnetic moment of coil } =\mathrm{NIA} \hat{\mathrm{j}}\) \(=\mathrm{Nl}\left(\pi \mathrm{r}^{2}\right) \hat{\mathrm{j}} \) Torque on loop (coil) \(=\overline{\mathrm{M}} \times \overline{\mathrm{B}}\)…
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