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JEE Mains · Physics · STD 12 - 12. atoms

In a hydrogen like ion, the energy difference between the \(2^{\text {nd }}\) excitation energy state and ground is 108.8 eV. The atomic number of the ion is

  1. A 4
  2. B 2
  3. C 1
  4. D 3
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Answer & Solution

Correct Answer

(D) 3

Step-by-step Solution

Detailed explanation

\(\Delta \mathrm{E}=13.6 \mathrm{z}^2\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right]\) \((13.6) \mathrm{z}^2\left[\frac{1}{1}-\frac{1}{9}\right]=108.8\) \(\frac{(13.6)(8)}{9}\left(z^2\right)=108.8\) \(\mathrm{z}=3\)
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