JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
If \(\mu_0\) and \(\varepsilon_0\) are the permeability and permittivity of free space, respectively, then the dimension of \(\left(\frac{1}{\mu_0 \varepsilon_0}\right)\) is :
- A \(\mathrm{L} / \mathrm{T}^2\)
- B \(L^2 / T^2\)
- C \(T^2 / L\)
- D \(\mathrm{T}^2 / \mathrm{L}^2\)
Answer & Solution
Correct Answer
(B) \(L^2 / T^2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}=\frac{1}{\sqrt{\mu_0 \varepsilon_0}} \Rightarrow \frac{1}{\mu_0 \varepsilon_0}=\mathrm{C}^2=\mathrm{L}^2 \mathrm{~T}^{-2}\)
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