ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Medium
  • Numerical

A uniform heating wire of resistance \(36\, \Omega\) is connected across a potential difference of \(240\, {V}\) The wire is then cut into half and potential difference of \(240\, {V}\) is applied across each half separately. The ratio of power dissipation in first case to the total power dissipation in the second case would be \(1: {x}\), where \({x}\) is........... .

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(4\)

Step-by-step Solution

Detailed explanation

First case \({P}_{1}=\frac{{V}^{2}}{{R}}=\frac{(240)^{2}}{36}\)

Second case Resistance of each half \(=18 \,\Omega\)

\({P}_{2}=\frac{(240)^{2}}{18}+\frac{(240)^{2}}{18}=\frac{(240)^{2}}{9}\)

\(\frac{{P}_{1}}{{P}_{2}}=\frac{1}{4}\)

\({x}=4.00\)

Same subject
Explore more questions on app