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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2022
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  • MCQ

In \(1^{\text {st }}\) case, Carnot engine operates between temperatures \(300\,K\) and \(100\,K\). In \(2^{\text {nd }}\) case, as shown in the figure, a combination of two engines is used. The efficiency of this combination (in \(2^{\text {ad }}\) case) will be.

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(A) same as the \(1^{\text {st }}\) case

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Detailed explanation

First case : \(\eta=1-\frac{100}{300}=\frac{2}{3}\)

Second case : \(\eta_{\text {net }}=\eta_{1}+\eta_{2}-\eta_{1} \eta_{2}\)

\(\eta_{1}=1-\frac{200}{300}=\frac{1}{3}\)

\(\eta_{2}=1-\frac{100}{200}=\frac{1}{2}\)

\(\eta_{\text {net }}=\frac{1}{3}+\frac{1}{2}-\frac{1}{6}=\frac{2}{3}\)

\(\eta\) (first case) \(=\eta\) (second case)

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