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JEE Mains · Physics · STD 12 - 12. atoms

Hydrogen atom is bombarded with electrons accelerated through a potential different of \(\mathrm{V}\), which causes excitation of hydrogen atoms. If the experiment is being formed at \(\mathrm{T}=0 \mathrm{~K}\). The minimum potential difference needed to observe any Balmer series lines in the emission spectra will be \(\frac{\alpha}{10} \mathrm{~V}\), where \(\alpha=\) _______.

  1. A \(456\)
  2. B \(158\)
  3. C \(121\)
  4. D \(498\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(121\)

Step-by-step Solution

Detailed explanation

For minimum potential difference electron has to make transition from \(n=3\) to \(n=2\) state but first electron has to reach to \(\mathrm{n}=3\) state from ground state. So, energy of bombarding electron should be equal to energy difference of \(n=3\) and \(n=1\) state.…
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