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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2024
  • Hard
  • Numerical

If Rydberg's constant is \(R\), the longest wavelength of radiation in Paschen series will be \(\frac{\alpha}{7 R}\), where \(\alpha=\)____________

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Answer & Solution

Correct Answer

(A) \(144\)

Step-by-step Solution

Detailed explanation

Longest wavelength corresponds to transition between \(n=3\) and \(n=4\)

\( \frac{1}{\lambda}=R Z^2\left(\frac{1}{3^2}-\frac{1}{4^2}\right)=R Z^2\left(\frac{1}{9}-\frac{1}{16}\right) \)

\( =\frac{7 R Z^2}{9 \times 16} \)

\( \Rightarrow \lambda=\frac{144}{7 R} \text { for } Z=1 \quad \therefore \alpha=144\)

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