JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2022
- Easy
- Numerical
For \(z=a^{2} x^{3} y^{\frac{1}{2}}\), where \(a\) is a constant. If percentage error in measurement of \(x\) and \(y\) are \(4 \%\) and \(12 \%\), respectively, then the percentage error for \(z\) will be \(%\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(18\)
Step-by-step Solution
Detailed explanation
\(z = a ^{2} x ^{3} y ^{1 / 2}\)
\(\frac{\Delta z }{ z }=\frac{2 \Delta a }{ a }+\frac{3 \Delta x }{ x }+\frac{1}{2}\frac{\Delta y }{ y }\)
\(a\) is constant
\(\frac{\Delta z}{z} \times 100=3(4 \%)+\frac{1}{2}(12 \%)=18%\)
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