JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
In the figure shown \(ABC\) is a uniform wire . If centre of mass of wire lies vertically below point \(A\) , then \(\frac{{BC}}{{AB}}\) is close to

- A \(1.85\)
- B \(1.5\)
- C \(1.37\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(1.37\)
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