JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2019
- Medium
- MCQ
Two very long, straight and insulated wires are kept at \(90^o\) angle from each other In \(xy -\) plane as shown in the figure. These wires carry current of equal magnitude \(I\), whose directions are shown in the figure. The net magnetic field at point \(P\) will be

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Answer & Solution
Correct Answer
(C) Zero
Step-by-step Solution
Detailed explanation
Magnetic field at point \(P\)
\(\overrightarrow{\mathrm{B}}_{\mathrm{net}}=\frac{\mu_{0} \mathrm{i}}{2 \pi \mathrm{d}}(-\hat{\mathrm{k}})+\frac{\mu_{0} \mathrm{i}}{2 \pi \mathrm{d}}(\hat{\mathrm{k}})=0\)
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