JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2023
- Medium
- Numerical
A nucleus disintegrates into two smaller parts, which have their velocities in the ratio \(3: 2\). The ratio of their nuclear sizes will be \(\left(\frac{x}{3}\right)^{\frac{1}{3}}\). The value of ' \(x\) ' is :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(\frac{ v _1}{ v _2}=\frac{3}{2}\)
\(m _1 v _1= m _2 v _2 \Rightarrow \frac{ m _1}{ m _2}=\frac{2}{3}\)
Since, Nuclear mass density is constant
\(\frac{ m _1}{\frac{4}{3} \pi r _1^3}=\frac{ m _2}{\frac{4}{3} \pi r _2^3}\)
\(\left(\frac{ r _1}{ r _2}\right)^3=\frac{ m _1}{ m _2}\)
\(\frac{ r _1}{ r _2}=\left(\frac{2}{3}\right)^{\frac{1}{3}}\)
\(\text { So, } x =2\)
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