JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
Two blocks (\(P\) and \(Q\)) with respectively masses \(2\) kg and \(1.5\) kg are joined by a massless thread. These blocks are mounted on a frictionless pulley which is fixed on the edge of a cube (\(S\)), as shown in the figure below. Block \(P\) is positioned on the top surface which has no friction and block \(Q\) is in contact with side-surface, having coefficient friction \(\mu\). The cube (\(S\)) moves towards the right with acceleration of \(\dfrac{g}{2}\), where \(g\) is gravitational acceleration. During this movement the block \(P\) and \(Q\) remain stationary. The value of \(\mu\) is _______. (take \(g = 10\) m/s\(^2\))
- A \(0.33\)
- B \(0.67\)
- C \(1\)
- D \(0.5\)
Answer & Solution
Correct Answer
(B) \(0.67\)
Step-by-step Solution
Detailed explanation
Let us analyze the forces acting on blocks \(P\) and \(Q\) in the non-inertial frame of reference of the cube \(S\), which is moving to the right with an acceleration \(a = \dfrac{g}{2} = 5 \text{ m/s}^2\). In this frame, a pseudo force acts on both blocks towards the left. For…
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