JEE Mains · Physics · STD 11 - 13. oscillations
For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is \(1\,kg\), the angular frequency is \(\omega_1\). When the mass block is \(2\,kg\) the angular frequency is \(\omega_2\). The ratio \(\omega_2 / \omega_1\) is

- A \(\sqrt{2}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(2\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\omega=\sqrt{\frac{ k }{ m }}\) \(\frac{\omega_2}{\omega_1}=\sqrt{\frac{ m _1}{ m _2}}=\sqrt{\frac{1}{2}}\)
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