Charges \(-q\) and \(+ q\) located at \(A\) and \(B\), respectively, constitute an electric dipole. Distance \(AB = 2a\), \(O\) is the mid point of the dipole and \(OP\) is perpendicular to \(AB\). A charge \(Q\) is placed at \(P\) where \(OP = y\) and \(y >> 2a\). The charge \(Q\) experiences an electrostatic force \(F\). If \(Q\) is now moved along the equatorial line to \(P'\) such that \(OP' = \frac{y}{3}\), the force on \(Q\) will be close to: \(\left( {\frac{y}{3} > > 2a} \right)\)

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Verified Solution

Answer & Solution

Correct Answer

(D) \(27F\)

Step-by-step Solution

Detailed explanation

\(\therefore F \propto \frac{1}{{{r^3}}}\)
Required force \(= 27\, F\).

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