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JEE Mains · Physics · STD 11 - Vectors
  • JEE Mains 2022
  • Hard
  • Numerical

A person moved from \(A\) to \(B\) on a circular path as shown in figure. If the distance travelled by him is \(60 \,m\), then the magnitude of displacement would be\(.....\,m\) (Given \(\left.\cos 135^{\circ}=-0.7\right)\)

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Answer & Solution

Correct Answer

(B) \(47\)

Step-by-step Solution

Detailed explanation

\(d = R \theta\)

\(60= R \left(\frac{3 \pi}{4}\right)\)

\(R =\frac{60 \times 4}{3 \pi}=\frac{80}{\pi} m\)

Displacement \(=\sqrt{ R ^{2}+ R ^{2}-2 R ^{2} \cos 135}\)

\(\Rightarrow \sqrt{2 R ^{2}-2 R ^{2}(-0.7)}\)

\(\Rightarrow \sqrt{3.4 R ^{2}}=\sqrt{3.4\left(\frac{80}{\pi}\right)^{2}}\)

\(\approx 47\,m\)

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