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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Consider a solid sphere of radius \(\mathrm{R}\) and mass density \(\rho(\mathrm{r})=\rho_{0}\left(1-\frac{\mathrm{r}^{2}}{\mathrm{R}^{2}}\right), 0<\mathrm{r} \leq \mathrm{R} .\) The minimum density of a liquid in which it will float is
- A \(\frac{\rho_{0}}{5}\)
- B \(\frac{\rho_{0}}{3}\)
- C \(\frac{2\rho_{0}}{3}\)
- D \(\frac{2\rho_{0}}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{2\rho_{0}}{5}\)
Step-by-step Solution
Detailed explanation
In case of minimum density of liqued, sphere will be floating while completely submerged So \(\mathrm{mg}=\mathrm{B}\) \(\mathrm{m}=\int_{0}^{\mathrm{R}} \rho\left(4 \pi \mathrm{r}^{2} \mathrm{dr}\right)=\mathrm{B}\)…
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