JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2026
- Medium
- MCQ
Match the LIST-I with LIST-II
| List-I | List-II |
|---|---|
| A. Planck's constant | I. \(ML^2T^{-2}\) |
| B. Stopping potential | II. \(T^{-1}\) |
| C. Work function | III. \(ML^2T^{-1}\) |
| D. Threshold frequency | IV. \(ML^2T^{-3}A^{-1}\) |
Choose the correct answer from the options given below:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) A-III, B-IV, C-I, D-II
Step-by-step Solution
Detailed explanation
The dimensional formula for Planck's constant \(h\) is obtained from \(E = h\nu\).
\([h] = \dfrac{[E]}{[\nu]} = \dfrac{ML^2T^{-2}}{T^{-1}} = ML^2T^{-1}\)
The dimensional formula for stopping potential \(V_0\) is obtained from \(eV_0 = E\).
\([V_0] = \dfrac{[E]}{[e]} = \dfrac{ML^2T^{-2}}{AT} = ML^2T^{-3}A^{-1}\)
Work function is a form of energy, so its dimensional formula is the same as that of energy.
\([\text{Work function}] = ML^2T^{-2}\)
Threshold frequency has the dimensional formula of frequency.
\([\text{Threshold frequency}] = T^{-1}\)
Therefore, the correct matching is A-III, B-IV, C-I, D-II.
Answer: A-III, B-IV, C-I, D-II
\([h] = \dfrac{[E]}{[\nu]} = \dfrac{ML^2T^{-2}}{T^{-1}} = ML^2T^{-1}\)
The dimensional formula for stopping potential \(V_0\) is obtained from \(eV_0 = E\).
\([V_0] = \dfrac{[E]}{[e]} = \dfrac{ML^2T^{-2}}{AT} = ML^2T^{-3}A^{-1}\)
Work function is a form of energy, so its dimensional formula is the same as that of energy.
\([\text{Work function}] = ML^2T^{-2}\)
Threshold frequency has the dimensional formula of frequency.
\([\text{Threshold frequency}] = T^{-1}\)
Therefore, the correct matching is A-III, B-IV, C-I, D-II.
Answer: A-III, B-IV, C-I, D-II
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