JEE Mains · Physics · STD 11 - 13. oscillations
Two simple harmonic motion, are represented by the equations \({y}_{1}=10 \sin \left(3 \pi {t}+\frac{\pi}{3}\right)\) \(y_{2}=5(\sin 3 \pi t+\sqrt{3} \cos 3 \pi t)\) Ratio of amplitude of \({y}_{1}\) to \({y}_{2}={x}: 1\). The value of \({x}\) is ...... .
- A \(2\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\({y}_{1}=10 \sin \left(3 \pi {t}+\frac{\pi}{3}\right) \Rightarrow \text { Amplitude }=10\) \({y}_{2}=5(\sin 3 \pi {t}+\sqrt{3} \cos 3 \pi {t})\) \({y}_{2}=10\left(\frac{1}{2} \sin 3 \pi {t}+\frac{\sqrt{3}}{2} \cos 3 \pi {t}\right)\)…
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