JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2021
- Hard
- Numerical
At very high frequencies, the effective impendance of the given circuit will be \(....\Omega\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\({X}_{{L}}=2 \pi {fL}\)
\({f}\) is very large
\(\therefore {X}_{{L}}\) is very large hence open circuit.
\({X}_{{C}}=\frac{1}{2 \pi {fC}}\)
\({f}\) is very large.
\(\therefore {X}_{{c}}\) is very small, hence short circuit.
Final circuit
\(Z_{e q}=1+\frac{2 \times 2}{2+2}=2\)
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