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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Hard
  • Numerical

At very high frequencies, the effective impendance of the given circuit will be \(....\Omega\)

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Answer & Solution

Correct Answer

(D) \(2\)

Step-by-step Solution

Detailed explanation

\({X}_{{L}}=2 \pi {fL}\)

\({f}\) is very large

\(\therefore {X}_{{L}}\) is very large hence open circuit.

\({X}_{{C}}=\frac{1}{2 \pi {fC}}\)

\({f}\) is very large.

\(\therefore {X}_{{c}}\) is very small, hence short circuit.

Final circuit

\(Z_{e q}=1+\frac{2 \times 2}{2+2}=2\)

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