JEE Mains · Physics · STD 12 -7. Alternating current
At very high frequencies, the effective impendance of the given circuit will be \(....\Omega\)
- A \(0.2\)
- B \(20\)
- C \(2.2\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\({X}_{{L}}=2 \pi {fL}\) \({f}\) is very large \(\therefore {X}_{{L}}\) is very large hence open circuit. \({X}_{{C}}=\frac{1}{2 \pi {fC}}\) \({f}\) is very large. \(\therefore {X}_{{c}}\) is very small, hence short circuit. Final circuit \(Z_{e q}=1+\frac{2 \times 2}{2+2}=2\)
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