JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2015
- Hard
- MCQ
If electronic charge \(e\), electron mass \(m\), speed of light in vacuum \(c\) and Planck 's constant \(h\) are taken as fundamental quantities, the permeability of vacuum \(\mu _0\) can be expressed in units of
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\left( {\frac{h}{{c{e^2}}}} \right)\)
Step-by-step Solution
Detailed explanation
Let \(\mu_{0}\) related with \(e, m, c\) and \(h\) as follows.
\(\mu_{0}=k e^{a} m^{b} c^{c} h^{d}\)
\({\left[M L T^{-2} A^{-2}\right]=[A T]^{a}[M]^{b}\left[L T^{-1}\right]^{c}\left[M L^{2} T^{-1}\right]^{d}}\)
\(=\left[M^{b+d} L^{c+2 d} T^{a-c-d} A^{a}\right]\)
On comparingboth sides we get
\(a=-2 \quad \ldots(i)\)
\(b+d=1 \ldots(i i)\)
\(c+2 d=1 \ldots(i i i)\)
\(a-c-d=-2 \ldots(i v)\)
By equations \((i),(i i),(i i i)\) and \((i v)\) we get,
\(a=-2, b=0, c=-1, d=1\)
\(\left[\mu_{0}\right]=\left[\frac{h}{c e^{2}}\right]\)
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