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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
To establish an instantaneous current of \(2\,A\) through a \(1\,\mu F\) capacitor ; the potential difference across the capacitor plates should be changed at the rate of
- A \(2\,\times 10^4\,V/s\)
- B \(4\,\times 10^6\,V/s\)
- C \(2\,\times 10^6\,V/s\)
- D \(4\,\times 10^4\,V/s\)
Answer & Solution
Correct Answer
(C) \(2\,\times 10^6\,V/s\)
Step-by-step Solution
Detailed explanation
As, \(C=\frac{Q}{V}=\frac{I t}{V}\) \(\Rightarrow \frac{V}{t}=\frac{I}{C}=\frac{2}{1 \times 10^{-6}}\) \(=2 \times 10^{6}\, \mathrm{V} / \mathrm{s}\)
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