JEE Mains · Physics · STD 12 -7. Alternating current
An \(LCR\) circuit contains resistance of \(110 \, \Omega\) and a supply of \(220\, V\) at \(300 \,rad / s\) angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by \(45^{\circ}\). If on the other hand, only inductor is removed the current leads by \(45^{\circ}\) with the applied voltage. The rms current flowing in the circuit will be ...... \(A\)
- A \(1\)
- B \(2.5\)
- C \(1.5\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(\tan 45^{\circ}=\frac{1}{\omega C R}=\frac{\omega L}{R} \Rightarrow X_{L}=X_{C}\) \(\Rightarrow\) resonance \(i =\frac{ V }{ R }\) \(=\frac{220}{110}=2 \,A\)
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