JEE Mains · Physics · STD 12 - 5. Magnetism and matter
At a certain place the angle of dip is \(30^{\circ}\) and the horizontal component of earth's magnetic field is \(0.5 G\). The earth's total magnetic field (in \(G\) ), at that certain place, is ................
- A \(\frac{1}{\sqrt{3}}\)
- B \(\frac{1}{2}\)
- C \(\sqrt{3}\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
\(B _{ H }= B \cos \theta\) \(\therefore B =\frac{ B _{ H }}{\cos \theta}=\frac{0.5 G }{\cos 30^{\circ}} \Rightarrow \frac{ G }{\sqrt{3}}\)
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