JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2019
- Hard
- Numerical
A parallel plate capacitor is of area \(6\, cm^2\) and a separation \(3\, mm\). The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants \(K_1 = 10, K_2 = 12\) and \(K_3 = 14\). The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be

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Answer & Solution
Correct Answer
(C) \(12\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}_{\mathrm{net}}=\mathrm{C}_{1}+\mathrm{C}_{2}+\mathrm{C}_{3}\)
\(\frac{\mathrm{k} \mathrm{AE}_{\mathrm{o}}}{\mathrm{d}}=\mathrm{k}_{1}\left(\frac{\mathrm{A}}{3}\right) \frac{\mathrm{E}_{\mathrm{o}}}{\mathrm{d}}+\mathrm{k}_{2}\left(\frac{\mathrm{A}}{3}\right) \frac{\mathrm{E}_{\mathrm{o}}}{\mathrm{d}}+\mathrm{k}_{3}\left(\frac{\mathrm{A}}{3}\right) \frac{\mathrm{E}_{\mathrm{o}}}{\mathrm{d}}\)
\(\mathrm{k}=\frac{\mathrm{k}_{1}+\mathrm{k}_{2}+\mathrm{k}_{3}}{3}=12\)
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