JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A body of mass 1 kg is suspended with the help of two strings making angles as shown in figure. Magnitude of tensions \(T_1\) and \(T_2\), respectively, are (in N) :
- A \(5,5 \sqrt{3}\)
- B \(5 \sqrt{3}, 5\)
- C \(5 \sqrt{3}, 5 \sqrt{3}\)
- D 5,5
Answer & Solution
Correct Answer
(B) \(5 \sqrt{3}, 5\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{T}_1=\mathrm{mg} \cos 30^{\circ} \\ & \mathrm{T}_2=\mathrm{mg} \sin 30^{\circ}\end{aligned}\)
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