JEE Mains · Maths · STD 12 - 7.1 indefinite integral
If \(\int\left(\frac{1}{x}+\frac{1}{x^3}\right) \left(\sqrt[23]{3 x^{-24}+x^{-26}}\right) d x \) \( =-\frac{\alpha}{3(\alpha+1)}\left(3 x^\beta+x^\gamma\right)^{\frac{\alpha+1}{\alpha}}+C, x \gt 0,\) \((\alpha, \beta, \gamma \in Z)\), where \(C\) is the constant of integration, then \(\alpha+\beta+\gamma\) is equal to ________ .
- A 19
- B 20
- C 21
- D 22
Answer & Solution
Correct Answer
(A) 19
Step-by-step Solution
Detailed explanation
\begin{aligned} & \int\left(\frac{1}{\mathrm{x}^2}+\frac{1}{\mathrm{x}^4}\right)\left(\frac{3}{\mathrm{x}}+\frac{1}{\mathrm{x}^3}\right)^{\frac{1}{23}} \mathrm{dx} \\ & \text { using } \mathrm{t}=\frac{3}{\mathrm{x}}+\frac{1}{\mathrm{x}^3} \Rightarrow…
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