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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2026
  • Hard
  • MCQ

The voltage and the current between \(A\) and \(B\) points shown in the circuit are _____.

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(24\) V, \(4\) A

Step-by-step Solution

Detailed explanation

The four parallel branches between the common left node \(A\) and the common right node are all identical: each consists of a \(27\text{ V}\) source in series with a \(3\ \Omega\) resistor. In the third branch, the two cells \((14\text{ V}\) and \(13\text{ V})\) aid each other, giving a net EMF of \(14 + 13 = 27\text{ V}\).

Thevenin equivalent between \(A\) and \(B\):
Since all four branches have the same EMF and polarity in parallel:
\(V_{th} = 27\text{ V}\)

The four \(3\ \Omega\) resistors in parallel give:
\(R_{th} = \dfrac{3}{4} = 0.75\ \Omega\)

Load branch (diagonal):
The diagonal connecting \(A\) and \(B\) consists of two \(3\ \Omega\) resistors in series, so:
\(R_L = 3 + 3 = 6\ \Omega\)

Current through the diagonal branch:
\(I = \dfrac{V_{th}}{R_{th} + R_L} = \dfrac{27}{0.75 + 6} = \dfrac{27}{6.75} = 4\text{ A}\)

Voltage across \(A\) and \(B\):
\(V_{AB} = I \cdot R_L = 4 \times 6 = 24\text{ V}\)

Hence, the voltage is \(24\text{ V}\) and the current is \(4\text{ A}\), which corresponds to option \((2)\ 24\text{ V},\ 4\text{ A}\).
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