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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2022
  • Hard
  • MCQ

A longitudinal wave is represented by \(x =10 \sin 2 \pi\left( nt -\frac{ x }{\lambda}\right) \,cm\). The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to .....................

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Answer & Solution

Correct Answer

(B) \(5 \pi\)

Step-by-step Solution

Detailed explanation

\(V _{ P } \max =4 V _{\text {wave }}\)

\(\omega A =4\left(\frac{\omega}{ k }\right) \Rightarrow A =\frac{4 \lambda}{2 \pi}\)

\(\lambda=\frac{2 \pi A }{4} \Rightarrow \frac{20 \pi}{4} \Rightarrow 5 \pi\)

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