JEE Mains · Physics · STD 11 - 14. waves and sound
A longitudinal wave is represented by \(x =10 \sin 2 \pi\left( nt -\frac{ x }{\lambda}\right) \,cm\). The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to .....................
- A \(2 \pi\)
- B \(5 \pi\)
- C \(\pi\)
- D \(\frac{5 \pi}{2}\)
Answer & Solution
Correct Answer
(B) \(5 \pi\)
Step-by-step Solution
Detailed explanation
\(V _{ P } \max =4 V _{\text {wave }}\) \(\omega A =4\left(\frac{\omega}{ k }\right) \Rightarrow A =\frac{4 \lambda}{2 \pi}\) \(\lambda=\frac{2 \pi A }{4} \Rightarrow \frac{20 \pi}{4} \Rightarrow 5 \pi\)
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