JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(T\) be the tangent to the ellipse \(E: x^{2}+4 y^{2}=5\) at the point \(P(1,1)\). If the area of the region bounded by the tangent \(T\), ellipse \(E\), lines \(x=1\) and \(x=\sqrt{5}\) is \(\alpha \sqrt{5}+\beta+\gamma \cos ^{-1}\left(\frac{1}{\sqrt{5}}\right)\), then \(|\alpha+\beta+\gamma|\) is equal to \(....\)
- A \(1.25\)
- B \(5\)
- C \(4\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(1.25\)
Step-by-step Solution
Detailed explanation
Tangent at \(\mathrm{P}: \mathrm{x}+4 \mathrm{y}=5\) Required Area \(=\int_{1}^{\sqrt{5}}\left(\frac{5-x}{4}-\frac{\sqrt{5-x^{2}}}{2}\right) \,d x\)…
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