JEE Mains · Physics · STD 12 -7. Alternating current
In the given circuit, the magnitude of \(V_{L}\) and \(V_{C}\) are twice that of \(V_{R}\). Given that \(f=50\,Hz\), the inductance of the coil is \(\frac{1}{ K \pi}\,mH\). The value of \(K\) is_________
- A \(0\)
- B \(1\)
- C \(2\)
- D \(7\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(V _{ L }= V _{ C }=2 V _{ R }\) \(X _{ L }= X _{ C }=2 R\) \(X _{ L }=10\,\Omega\) \(\omega L =10\) \(2 \pi f =10\) \(L =\frac{10}{2 \pi f }=\frac{1}{10 \pi}\,H =\frac{1000}{10 \pi}\,mH\) \(L =\frac{1}{\frac{1}{100} \pi} ; \quad K =\frac{1}{100}=0.01 \approx 0\)
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