JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2022
- Medium
- Numerical
In the given circuit, the magnitude of \(V_{L}\) and \(V_{C}\) are twice that of \(V_{R}\). Given that \(f=50\,Hz\), the inductance of the coil is \(\frac{1}{ K \pi}\,mH\). The value of \(K\) is_________

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Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(V _{ L }= V _{ C }=2 V _{ R }\)
\(X _{ L }= X _{ C }=2 R\)
\(X _{ L }=10\,\Omega\)
\(\omega L =10\)
\(2 \pi f =10\)
\(L =\frac{10}{2 \pi f }=\frac{1}{10 \pi}\,H =\frac{1000}{10 \pi}\,mH\)
\(L =\frac{1}{\frac{1}{100} \pi} ; \quad K =\frac{1}{100}=0.01 \approx 0\)
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