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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2021
  • Medium
  • MCQ

A player kicks a football with an initial speed of \(25\, {ms}^{-1}\) at an angle of \(45^{\circ}\) from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g \(=10 \,{ms}^{-2}\) )

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Answer & Solution

Correct Answer

(C) \({h}_{\max }=15.625\, {m} \quad {T}=1.77 \,{s}\)

Step-by-step Solution

Detailed explanation

\({H} =\frac{{U}^{2} \sin ^{2} \theta}{2 {g}}\)

\(=\frac{(25)^{2} \cdot(\sin 45)^{2}}{2 \times 10}\)

\(=15.625 {m}\)

\({T} =\frac{{U} \sin \theta}{{g}}\)

\(=\frac{25 \times \sin 45^{\circ}}{10}\)

\(=2.5 \times 0.7\)

\(=1.77\, {s}\)

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