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JEE Mains · Physics · STD 11 - 3.2 motion in plane
A player kicks a football with an initial speed of \(25\, {ms}^{-1}\) at an angle of \(45^{\circ}\) from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g \(=10 \,{ms}^{-2}\) )
- A \({h}_{\max }=10\, {m} \quad {T}=2.5\, {s}\)
- B \({h}_{\max }=15.625\, {m} \quad {T}=3.54 \,{s}\)
- C \({h}_{\max }=15.625\, {m} \quad {T}=1.77 \,{s}\)
- D \({h}_{\max }=3.54 \,{m} \quad {T}=0.125 \,{s}\)
Answer & Solution
Correct Answer
(C) \({h}_{\max }=15.625\, {m} \quad {T}=1.77 \,{s}\)
Step-by-step Solution
Detailed explanation
\({H} =\frac{{U}^{2} \sin ^{2} \theta}{2 {g}}\) \(=\frac{(25)^{2} \cdot(\sin 45)^{2}}{2 \times 10}\) \(=15.625 {m}\) \({T} =\frac{{U} \sin \theta}{{g}}\) \(=\frac{25 \times \sin 45^{\circ}}{10}\) \(=2.5 \times 0.7\) \(=1.77\, {s}\)
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