JEE Mains · Physics · STD 12 -7. Alternating current
An inductor of reactance \(100 \Omega\), a capacitor of reactance \(50 \Omega\), and a resistor of resistance \(50 \Omega\) are connected in series with an AC source of 10 V , 50 Hz. Average power dissipated by the circuit is ________ W.
- A 5
- B 4
- C 3
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{P}=\mathrm{V}_{\mathrm{rms}} \mathrm{I}_{\mathrm{rms}} \cos \phi \\ & \mathrm{P}=\mathrm{V}_{\mathrm{rms}} \times \frac{\mathrm{V}_{\mathrm{rms}}}{\mathrm{z}} \times \frac{\mathrm{R}}{\mathrm{z}} \\ & \mathrm{P}=\mathrm{V}_{\mathrm{rms}}^2 \times…
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