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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Hard
  • MCQ

An alternating current is given by the equation \(i=i_{1} \sin \omega t+i_{2} \cos \omega t\). The rms current will be

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Answer & Solution

Correct Answer

(A) \(\frac{1}{\sqrt{2}}\left(i_{1}^{2}+i_{2}^{2}\right)^{\frac{1}{2}}\)

Step-by-step Solution

Detailed explanation

\(i = i _{1} \sin \omega t + i _{2} \sin (\omega t +90)\)

\(i_0 =\sqrt{ i _{1}^{2}+ i _{2}^{2}}\)

\(i _{ rms }=\frac{ i _{0}}{\sqrt{2}}=\frac{\sqrt{ i _{1}^{2}+ i _{2}^{2}}}{\sqrt{2}}\)

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