JEE Mains · Physics · STD 12 - 3. current electricity
The charge accumulated on the capacitor connected in the following circuit is________ \(\mu \mathrm{C}\) (Given \(\mathrm{C}=150\ \mu \mathrm{F}\))
- A \(400\)
- B \(700\)
- C \(500\)
- D \(460\)
Answer & Solution
Correct Answer
(A) \(400\)
Step-by-step Solution
Detailed explanation
\( V_A+\frac{10}{3}(1)-6(1)=V_B \) \( V_A-V_B=6-\frac{10}{3}=\frac{8}{3} \text { volt } \) \( Q=C\left(V_A-V_B\right) \) \( =150 \times \frac{8}{3}=400 \mu C\)
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