JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2024
- Hard
- Numerical
The charge accumulated on the capacitor connected in the following circuit is________ \(\mu \mathrm{C}\) (Given \(\mathrm{C}=150\ \mu \mathrm{F}\))

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Answer & Solution
Correct Answer
(A) \(400\)
Step-by-step Solution
Detailed explanation
\( V_A+\frac{10}{3}(1)-6(1)=V_B \)
\( V_A-V_B=6-\frac{10}{3}=\frac{8}{3} \text { volt } \)
\( Q=C\left(V_A-V_B\right) \)
\( =150 \times \frac{8}{3}=400 \mu C\)
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