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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2024
  • Hard
  • Numerical

The charge accumulated on the capacitor connected in the following circuit is________ \(\mu \mathrm{C}\) (Given \(\mathrm{C}=150\  \mu \mathrm{F}\))

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Answer & Solution

Correct Answer

(A) \(400\)

Step-by-step Solution

Detailed explanation

\( V_A+\frac{10}{3}(1)-6(1)=V_B \)

\( V_A-V_B=6-\frac{10}{3}=\frac{8}{3} \text { volt } \)

\( Q=C\left(V_A-V_B\right) \)

\( =150 \times \frac{8}{3}=400 \mu C\)

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