JEE Mains · Physics · STD 12 - 3. current electricity
An electric toaster has resistance of \(60\ \Omega\) at room temperature \(\left(27^{\circ} \mathrm{C}\right)\). The toaster is connected to a \(220 \mathrm{~V}\) supply. If the current flowing through it reaches \(2.75 \mathrm{~A}\), the temperature attained by toaster is around _______. (if \(\alpha=2 \times 10^{-4} /{ }^{\circ} \mathrm{C}\) )
- A \(694^{\circ} \mathrm{C}\)
- B \(1235^{\circ} \mathrm{C}\)
- C \(1694^{\circ} \mathrm{C}\)
- D \(1667^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(1694^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{R}_{\mathrm{T}=27}=60 \Omega, R_T=\frac{220}{2.75}=80 \Omega \) \( \mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T}) \) \( 80=60\left[1+2 \times 10^{-4}(\mathrm{~T}-27)\right] \) \( \mathrm{T} \approx 1694^{\circ} \mathrm{C}\)
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