JEE Mains · Physics · STD 12 - 1. Electric charges and fields
An electric dipole is placed on \({x}\)-axis in proximity to a line charge of linear charge density \(3.0 \times 10^{-6}\, {C} / {m}\). Line charge is placed on \(z-\)axis and positive and negative charge of dipole is at a distance of \(10\, {mm}\) and \(12\, {mm}\) from the origin respectively. If total force of \(4\, {N}\) is exerted on the dipole, find out the amount of positive or negative charge of the dipole.
- A \(815.1\, {nC}\)
- B \(8.8\, \mu {C}\)
- C \(0.485 \,{mC}\)
- D \(4.44\, \mu {C}\)
Answer & Solution
Correct Answer
(D) \(4.44\, \mu {C}\)
Step-by-step Solution
Detailed explanation
\(r=10 \,{mm}, {x}=2\) \(\left|\overrightarrow{{F}}_{{q}}\right|=\frac{2 {k} \lambda}{{r}} \cdot {q}\) \(\left|\vec{F}_{-q}\right|=\frac{2 k \lambda}{r+x} \cdot q\) \(\Rightarrow \quad\left|\vec{F}_{\text {net }}\right|=\frac{2 k \lambda q}{r}-\frac{2 k \lambda q}{r+x}\)…
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