JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2022
- Medium
- MCQ
Nucleus A is having mass number \(220\) and its binding energy per nucleon is \(5.6 \,MeV\). It splits in two fragments '\(B\)' and '\(C\)' of mass numbers \(105\) and \(115\) The binding energy of nucleons in '\(B\)' and '\(C\) ' is \(6.4 \,MeV\) per nucleon. The energy \(Q\) released per fission will be............\(MeV\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(176\)
Step-by-step Solution
Detailed explanation
\(Q=(B \cdot E)_{p}-(B . E)_{R}\)
\(=(105+115)(6.4)-(220)(5.6)\)
\(=176 \,MeV\)
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