JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
One mole of an ideal gas passes through a process where pressure and volume obey the relation \(P\, = {P_0}\,\left[ {1 - \frac{1}{2}{{\left( {\frac{{{V_0}}}{V}} \right)}^2}} \right]\). Here \(P_0\) and \(V_0\) are constants. Calculate the change in the temperature of the gas if its volume change from \(V_0\) to \(2V_0\)
- A \(\frac{1}{4}\frac{{{P_0}{V_0}}}{R}\)
- B \(\frac{1}{2}\frac{{{P_0}{V_0}}}{R}\)
- C \(\frac{5}{4}\frac{{{P_0}{V_0}}}{R}\)
- D \(\frac{3}{4}\frac{{{P_0}{V_0}}}{R}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{4}\frac{{{P_0}{V_0}}}{R}\)
Step-by-step Solution
Detailed explanation
\(n=1\) mole \(P=P_{0}\left\{1-\frac{1}{2}\left(\frac{V_{0}}{V}\right)^{2}\right\} \quad ; \quad P V=n R T=R T\) \(P=\frac{R T}{V}\) \(\frac{R T}{V}=P_{0}\left\{1-\frac{V_{0}^{2}}{2 V^{2}}\right\}\)…
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